Percezione uditiva Corso di Principi e Modelli della Percezione Prof. Giuseppe Boccignone Dipartimento di Informatica Università di Milano [email protected] http://boccignone.di.unimi.it/PMP_2016.html Cos’è il suono? • I suoni sono creati dalle vibrazioni degli oggetti • Le vibrazioni di oggetti producono vibrazioni nelle molecole in prossimità degli oggetti stessi. • Questo causa differenze di pressione nell’aria che si propagano in ogni direzione (Es. sasso nello stagno) Cos’è il suono? • Le onde sonore viaggiano con una certa velocità di propagazione • Questa dipende dal mezzo di trasmissione. • Esempio: La velocità del suono attraverso l’aria è di circa 340 metri al secondo, ma nell’acqua essa cresce sino a 1500 metri al secondo Velocita’ 340 m/sec 1200 km/ora Cos’è il suono? • Caratteristiche fisiche delle onde sonore – Ampiezza: Grandezza del profilo di variazione di pressione dell’onda sonora – Intensità: Quantità di energia di un suono che cade su una unità di area – Frequenza: Per i suoni è il numero di cicli (in termini di variazione di pressione) che si ripetono in un secondo • Caratteristiche psicologiche delle onde sonore – Volume (loudness): L’aspetto psicologico del suono correlato alla intensità percepita – Altezza (pitch): L’aspetto psicologico del suono correlato alla frequenza percepita Caratteristiche del suono dipende da un insieme di proprietà spettrali (armoniche, ecc) Livello psicologico Livello fisico Pitch Frequenza Cos’è il suono? //Ampiezza e frequenza dipende da frequenza, rumore, ambiente acustico Loudness Ampiezza / Intensità Cos’è il suono? //Ampiezza e frequenza • L’udito degli umani è sensibile ad un ampio range di intensità • Il rapporto fra il volume più basso e quello più alto di un suono che risulta percepibile è quasi di uno su un milione • Al fine di descrivere differenze in ampiezza, i livelli del suono sono misurati su una scala logaritmica le cui unità sono i decibels (dB) • Cambiamenti relativamente piccoli in decibel possono corrispondere a cambiamenti fisici molto consistenti (un incremento di 6 decibel corrisponde circa ad un raddoppio della pressione del suono) dB = 20 log(p/po) per p = po, dB = 0 Cos’è il suono? //Ampiezza e frequenza • La frequenza è associata con l’altezza (pitch) di un suono • Suoni a basse frequenze corrispondono a suoni “bassi” (e.g., i suonati da una tuba) • Suoni ad alta frequenze corrispondono a suoni “acuti” (e.g., i suonati da un clarino) Cos’è il suono? //Ampiezza e frequenza • La frequenza è associata con l’altezza di un suono • L’udito degli umani è sensibile ad un ampio range di frequenze: da circa 20 a 20,000 Hz Cos’è il suono? //Ampiezza e frequenza: rumori ambientali Cos’è il suono? //Sinusoidi e toni puri • Uno dei più semplici tipi di suoni: onde sinusoidali = toni puri • Onde sinusoidali: Onde per cui le variazioni in funzione del tempo sono descritte da un’ onda sinusoidale • Il tempo per un ciclo completo dell’onda sinusoidale è definito periodo • Ci sono 360 gradi di fase in un intero periodo Diapason Cos’è il suono? //Sinusoidi e toni puri Cos’è il suono? //Sinusoidi e toni puri Periodo: Equazione di un'onda progressiva : Numero d'onda: Equazione di un'onda retrograda : Pulsazione: Frequenza: Velocità: Trigonometric functions and sound Cos’è il suono? The sounds we hear are caused by vibrations that send pressure waves through the air. Our ears respond to these pressure waves and signal the brain about their amplitude and frequency, and the brain interprets those signals as sound. In this paper, we focus on how sound is generated and imagine generating sounds using a computer with a speaker. Sound Waves //Funzioni trigonometriche e suono Once cycle of sin(2π t) sin(2 π t) 1 • Loud Una “cassa” è speakers fatta diproduce sound by Frequency of oscillation – The diaphragm of the speaker moves out, pushing air molecules una componente vibrando together che We need- to describe oscillations thatvibra occure many 0.5 – The diaphragm also moves in, pulling genera onde di pressione times per second. The graph of a sine function thatthe air molecules apart The cycle of this process creates alternating high- and low-pressure - through un elettromagnete genera oscillates one– cycle ache second looks like: regionsin that travel through the air 0 l’oscillazione −0.5 A function that oscillates 440 times per second will look more like this. Note that the time axis only runs to 1/20 of a second. −1 0 0.2 0.4 0.6 Time t in seconds 0.8 1 Once cycle of sin(2π 440 t) 1 We say that the oscillation is 440 Hertz, or 440 cycles per second. sin(2 π 440 t) 0.5 Inviando una corrente elettrica variabile all’elettromagnete, questo fa oscillare la Generating sound with a computer speaker “membrana” 0 A speaker usually consists of a paper cone attached to −0.5 an electromagnet. By sending an oscillating electric Se l’oscillazione è di 440 cicli per current through the electromagnet, the paper cone can −1 secondo (Hz), viene generata la nota LA 0 0.01 0.02 0.03 0.04 0.05 be made to oscillate back and forth. If you make a Time t in seconds speaker cone oscillate 440 times per second, it will sound like a pure A note. Click here to listen. If you make a speaker cone oscillate 880 times per second, it will sound like an A, but one octave higher. Click here to listen. We’ll call this A2. On a sin(2 π 440 t) 0.5 Cos’è il suono? 0 Speaker location //Funzioni trigonometriche e suono ith a computer speaker nsists of a paper cone attached to −0.5 sending an oscillating electric ectromagnet, the paper cone can −1 0 0.01 0.02 0 ack and forth. If you make a Time t in seco Se l’oscillazione è di 440 times per second, it will 880 Hz viene generata la nota LAlisten. If you make a speaker cone oscillate 8 ote. Click here to ma di un’ottava superiore ike an A, but(LA2) one octave higher. Click here to listen. We’ll cal 1760 Hz ottengo raphs ofA the location of the speaker cone as a function of time, e LA3 Raising the frequency to 1760 Hertz raises the pitch another o de of oscillation, that is, how high and how low the graph goes, d the speaker cone goes, changes the volume of the sound. The he amplitude of an oscillation of 1760 Hertz rising from 0 to 1. Cos’è il suono? g volume A3 four times. A (440 Hz) 4 2 0 −2 −4 0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04 0.045 Time (seconds) 0.05 0.03 0.035 A (880 Hz) 4 2 0 −2 −4 0 0.005 0.01 0.015 0.02 0.025 0.04 0.045 0.05 0.04 0.045 0.05 0.04 0.045 0.05 A (1760 Hz) getting louder 0.1 0 −0.1 0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 A−C#−E chord (440, 554, 659 Hz) 4 2 0 −2 −4 0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 A−C#−E−A2 chord (440, 554, 659, 880 Hz) 5 //Funzioni trigonometriche e suono 0 or scalesEsempio: scala cromatica la frequenza di oscillazione per ncreasesAumenta the frequency of oscillation by 12 steps from one octav passi di 1/12 frequencies of the chromatic scale would be −5 0 0.005 1 12 0.01 0.015 2 12 0.02 0.025 0.03 0.035 12 12 0.04 0.045 0.05 440 ⋅ 2 0 ,440 ⋅ 2 ,440 ⋅ 2 ,K 440 ⋅ 2 = 880 etween hasLAa name of its own; they are: A, A#, B, C, C#, D, D# LA# SI DO, DO#,RE,RE#,MI,FA,FA#,SOL,SOL# LA2 le starts at 440 Hertz, then increases over 8 steps to A2, along th D (5/12), E (7/12), F# (9/12), G# (11/12) and A2 (12/12). A grap n an A-major scale can be found on a later page. Click here to l Cos’è il suono? //Funzioni trigonometriche e suono Speaker position A−major scale A 440 Hz 1 B 493.88 Hz 0.5 0 −0.5 −1 0 0.02 0.04 0.06 0.08 0.1 Time C# 554.37 Hz 1 0.12 0.14 0.16 0.18 0.2 0.36 0.38 0.4 0.54 0.56 0.58 0.6 0.74 0.76 0.78 0.8 D 587.33 Hz 0.5 0 −0.5 −1 0.2 0.22 0.24 0.26 0.28 0.3 E 659.26 Hz 1 0.32 0.34 F# 739.99 Hz 0.5 0 −0.5 −1 0.4 1 0.42 0.44 0.46 0.48 0.5 G# 830.61 Hz 0.52 A 880 Hz 0.5 0 −0.5 −1 0.62 0.64 0.66 0.68 0.7 0.72 Cos’è il suono? e sounds sovrapposizione di suoni Chords and//accordi superposition of A chord is formed by playing multiple notes at once. You could play a chord with three notes by accordo è ottenuto suonando putting threeUn speakers side by side and making più each oscillate at the right frequency for a different note. note contemporaneamente Or, you can add together the functions for each frequency to make a more complicated oscillatory function and make your speaker cone oscillate according to that function. For example, if you want to Esempio: accordo di LA maggiore play an A – C# - E chord, you can separately make three speakers oscillate according to the functions: sin( 440 ⋅ 2πt ), 4 sin( 440 ⋅ 2 12 ⋅ 2πt ), 7 sin( 440 ⋅ 2 12 ⋅ 2πt ) If you want one note louder or softer than the others, you can multiply the whole function by a constant LA of that note. Each DO# speaker will make MI pressure waves in the air, and to increase or decrease the volume these pressure waves from different speakers will overlap as they move toward your ear. By the time they are at your ear, you will be unable to tell which speaker they came from; the pressure waves will have been superimposed on one another, or added to one another. Your ear is amazing at being able to respond to the different frequencies separately to perceive the three notes being played at once. This explains why you can simply add the three functions above and make the speaker cone of a single speaker oscillate following the sum: 4 7 sin( 440 ⋅ 2πt ) + sin( 440 ⋅ 2 12 ⋅ 2πt ) + sin( 440 ⋅ 2 12 ⋅ 2πt ) Here again, if you want the different notes to have different volumes, you can multiply each sine wave by a constant. Click here to hear an A – C# - E chord. Click here to hear an A – C# - E – A2 chord. The graphs on the preceding page show what happens when you add the three functions to make the A – Or, you can add together the functions for each frequency to make a more complicated oscillatory function and make your speaker cone oscillate according to that function. For example, if you want to play an A – C# - E chord, you can separately make three speakers oscillate according to the functions: 4 12 sin( 440 ⋅ 2πt ), sin( 440 ⋅ 2 ⋅ 2πt ), 7 12 sin( 440 ⋅ 2 ⋅ 2πt ) Cos’è il suono? If you want one note louder or softer than the others, you can multiply the whole function by a constant o increase or decrease the volume of that note. Each speaker will make pressure waves in the air, and e sovrapposizione hese pressure//accordi waves from different speakers will overlap as di theysuoni move toward your ear. By the time hey are at your ear, you will be unable to tell which speaker they came from; the pressure waves will have been superimposed Possiamo: on one another, or added to one another. Your ear is amazing at being able to respond to the-different separately toleperceive thetre three notesdiversi being played at once. This generarefrequencies contemporaneamente tre note su speaker explains why you can simply thee three functions and su make the speaker cone of a single - sommare le treadd note generare l’ondaabove ottenuta, un unico speaker speaker oscillate following the sum: 4 12 7 12 sin( 440 ⋅ 2πt ) + sin( 440 ⋅ 2 ⋅ 2πt ) + sin( 440 ⋅ 2 ⋅ 2πt ) Here again, if you want the different notes to have different volumes, you can multiply each sine wave Pure A (440 Hz) A−C#−E chord (440, 554, 659 Hz) by a constant. 1 Speaker cone location Speaker cone location 1 Click here to hear an A –0.5C# - E chord. Click here to hear an 0.5 A – C# - E – A2 chord. The graphs on the preceding page show what happens when you add the three functions to make the A – 0 0 C# - E chord and the A – C# - E – A2 chord. −0.5 −0.5 Strength Strength −1 −1 Frequency spectrum 0 0.01 0.02 0.03 0.04 0.05 0 0.04 0.05 The sounds we have generated so far are very simple, being sine functions or0.01 sums0.02 ofTime a 0.03 few sine Time functions, and they sound very much computer-generated. morespectrum complex, and chord it isn’t Frequency spectrum for pure A Real sounds are Frequency for A−C#−E 5 1.5 Sono possibilità equivalenti: al nostro orecchio comunque arrivano entirely clear that sine functions have anything to do with them. However, it cansovrapposte be shown that any Pure A A−C#−E chord 4 “continuous” sound (that is, a sound that is constant, or unchanging over time) can be reproduced as a 1 sum of sine functions of different3 frequencies and amplitudes. That is, if a speaker is playing a continuous sound by making the 2speaker cone follow some function L(t) over the time interval from 0 0.5 o 1 second, then we can write L(t) as a sum of sine functions this way: Cos’è il suono? 1 0 20 , 000 400 600 800 1000 Frequencyk k = 20for spoken long A Frequency spectrum L (t ) = ∑ a //spettro di frequenza 0 200 0 sin( k ⋅ 2πt ) 0 200 400 600 Frequency 800 1000 Frequency spectrum for spoken long E Strength 0 0.5 0 0.5 0 200 1 400 600 Frequency Speaker cone location Speaker cone location Strength 1 The number k is the frequency, and for sounds that humans can hear,0.8we should use frequencies from Chords superposition of sounds 20 Hertz to about 20,000 Hertz. As del we tono age,and we can’t hear sounds 20,000 Hertz very che well anymore. 0.8 Notiamo come l’onda puro LA sia molto più at “semplice” dell’onda 0.6 A chord is formed by playing multiple notes at once. You could play a chord with three no 20 Hz, 60 Hz, (the sound of mechanical devices that hum because of alternating current Click here for:corrisponde all’accordo 0.6 putting three speakers side by side and making each oscillate at the right frequency for a dif 0.4 being 60 Hz) 100 Hz, 10000 Hz, 16000 Hz,can 20000Hz. Bethe aware thatfor some these may be outside the Or, you add together functions eachof frequency to make a more complicated osci 0.4 Pure A (440 Hz) A−C#−E chord (440, 554, 659 Hz) range of your speakers or your ears! function The numbers are called the amplitudes for frequency k. It is and makeayour speaker cone oscillate according to that function. For example, if y k 0.2 0.2 play an A – C# E chord, you can separately make three speakers oscillate according to the 1 1 easy to find the values of a k using integrals: 4 7 0 sin(440 ⋅ 2πt ), 800 1000 0.5 sin( ⋅ 2 12 ⋅ 2400 πt ), 0 440200 a = ∫ sin(k ⋅ 2πt ) L(t )dt. sin( 440800 ⋅ 2 12 ⋅1000 2πt ) 600 Frequency If youk want one note louder or softer than the Frequency others, you can multiply the whole function b Frequency spectrum for spoken long O spectrum for spoken OO 0 0 to increase or decrease the volume of that 0.8 note. Each speaker will make pressure waves in waves from different will need overlaptoasuse theycosine move toward your ear. B (Actually,Chords this isn’t whole story –these for pressure this to be exactly correct,speakers you either and the superposition of sounds −0.5 −0.5 0.4 0.6 they are at your ear, you will be unable to tell which speaker they came from; the pressure w functions Aorchord you need to be tomultiple shift each function horizontally onwith thethree t axis, but is close is formed by able playing notessine at once. You could play a chord notes by this Frequency spectrum for pure A 5 4 12 Strength Strength 0.3 side have superimposed onatone or addedfor toaone another. Your ear is amazing at b putting three and been making each oscillate theanother, right frequency different note. −1 speakers side by −1 0.4 respond to the different frequencies separately to perceive the three notes being played at o Or, you can0add together the for each frequency to make0 a more complicated oscillatory 0.2functions 0.01 0.02 0.03 0.04 0.05 0.01 0.02 0.03 0.04 explains why according you can simply the three above and make 0.05 the speaker cone of a function and make your speaker cone oscillate to thatadd function. Forfunctions example, Time Timeif you want to 0.2 0.1 can speaker oscillate the sum: play an A – C# - E chord, you separately makefollowing three speakers oscillate according to the functions: 1.5 Frequency spectrum 4 for A−C#−E chord 7 7 12 Strength Strength 440 ⋅ 2π⋅ t2) +⋅sin( ⋅ 2 ⋅ 2400 πt ) + sin( ⋅ 2 ⋅ 21000 πt ) sin( 440 ), sin( 440 ⋅ 2600 ⋅ 2πt800 ),sin(sin( 440 20πt )440200 0 ⋅ 2πt200 1000 600440 800 Pure A400 Frequency Frequency Here again, if you want the different notes to have different volumes, you can multiply each A−C#−E chord 4 one note louder or softer than the others, you can multiply the whole function by If you want a constant byofa that constant. to increase or decrease the volume note. Each speaker will waves in the air,frequenza and 1 make pressure frequenza frequenza frequenza 3 these pressure waves from different speakers will overlap as they move toward your ear. By the time here to hear anthey A –came C# - from; E chord. Click here to hear they are at your ear, you will be unable toClick tell which speaker the pressure waves willan A – C# - E – A2 chord 2 graphs on preceding page0.5 show what when you add have been superimposed on one another, or the added to one another. Your earhappens is amazing at being ablethe to three functions to make respond to1the different frequencies being played at once. This C#separately - E chord to andperceive the A –the C#three - E –notes A2 chord. explains why you can simply add the three functions above and make the speaker cone of a single 0 12 0 12 aker cone oscillate according to that function. 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It is by a constant. 1 frequenza frequenza frequenza 3 # - E – A2 chord. using integrals: C# -chord. E chord.The Click here to hear an A – C# - E – A2 chord k to hear an A – C# - E chord. Click here toClick re hearhere an Ato–hear C#an - EA –– A2 7 12 Strength Strength 4 12 2 graphs preceding page0.5 showtowhat happens eceding page show what 1happens when you on addthethe three functions make the Awhen – you add the three functions to make C# E chord and the A – C# E – A2 chord. d the A – C# - E – 1A2 chord. Strength 0 0.5 L (t ) = 20 , 000 Speaker cone location Speaker cone location Strength a = sin(k ⋅ 2πt ) L(t )dt. ted so far Cos’è are00kvery∫200 being sine functions ilsimple, suono? 0 or sums of a few sine Frequency spectrum 400 600 800 1000 0 200 400 600 800 1000 0 ctrum The sounds we have generated so far are very simple, being sine functions or sums of a few Frequency Frequency ery much computer-generated. 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Your ear is amazing at b 0 Hz, 10000 Hz, 16000 Hz, 20000Hz.(udibile) Be aware that some of these may be outside the 0.6 −1 −1 1 respond to the different frequencies separately to perceive the three notes being played at o eakers or numbers are for k. kIt⋅ 2is ertz. Asyour weears! age, can’t sounds at 20,000 Hertz very well anymore. 0.3 0 Thewe 0.01 0.02a khear 0.03called 0.04the amplitudes 0.05 0 frequency 0.01 0.02 0.03 0.04 0.05 a = sin( π t ) L ( t ) dt . k functions explains why you can simply0.4 add the three ∫0 Timeabove and make the speaker cone of a Time ampiezza per la frequenza k values of sound integrals: a k using speaker oscillate following the sum: z, (the of mechanical devices that hum because of alternating current 0.2 Frequency for A−C#−E chord isn’t the whole story – for thisspectrum to be 4exactly correct, you 7either need to use c 1.5 12 0.2 functions or you need to be able to shift each sine function horizontally sin(440 ⋅ 2πt ) + sin(440 ⋅ 2 ⋅ 2πt ) + sin(440 ⋅ 2 12on⋅ 2the πt ) t axis, but th a k = sin(k ⋅ 2πt )Pure L(t )Adt. Here again, if you want the different notes to have different volumes, A−C#−E chord you can multiply each 0 0 k by600 a constant. 10 200 400 800 1000 200 frequenza 400 600 800 1000 frequenza frequenza 0 Hz, 16000 Hz, 20000Hz. Be aware that some of these may be outside the ∫ our ears! The40 numbers a are called the amplitudes for frequency k. It is sn’t the whole story30– for this to be exactly correct, you either need to use cosine to be able to shift each sineFrequency function horizontally the isFrequency close using integrals: Click here toon hear antAaxis, – C#but - E this chord. Click here to hear an A – C# - E – A2 chord k need 2 1 1 graphs on the preceding page0.5 show what happens when you add the three functions to make C# - E chord and the A – C# - E – A2 chord. a = sin(k ⋅ 2πt ) L(t )dt. 1 Strength Strength 5 0.1 Chords and superposition of sounds A chord is formed by playing multiple notes at once. You could play a chord with three notes by putting three speakers side by side and making each oscillate at the right frequency for a different Or, you can add together the functions for each frequency to make a more complicated oscillatory function and make your speaker cone oscillate according to that function. For example, if you wa play an A – C# - E chord, you can separately make three speakers oscillate according to the functi Cos’è il suono? //spettro di frequenza 4 7 12 sin(440 ⋅ 2πA−C#−E t ), sin( 440 ⋅ 2554, ⋅659 2πHz) t ), chord (440, Pure A (440 Hz) sin( 440 ⋅ 2 12 ⋅ 2πt ) 0 Speaker cone location Strength Speaker cone location Speaker cone location Speaker cone location If you want one note louder or1 softer than the others, you can multiply the whole function by a con to increase or decrease the volume of that note. Each speaker will make pressure waves in the air, 0.5 0.5 theseofpressure Chords and superposition sounds waves from different speakers will overlap as they move toward your ear. By the ti 0 0 they are at yournotes ear, you will be unable tellawhich they came A chord is formed by playing multiple at once. You couldtoplay chord speaker with three notes byfrom; the pressure waves w Pure A (440 Hz) A−C#−E chord (440, 554, 659 Hz) have been superimposed on one another, or added to one another. Your ear is amazing at being ab −0.5speakers side by side and making each −0.5 putting three oscillate at the right frequency for a different note. 1 1 to the for different frequencies separately to complicated perceive the oscillatory three notes being played at once. T Or, you can −1 add togetherrespond the functions each frequency to make a more −1 explains why oscillate you can simply add the three functions above and the speaker cone of a single function and 0.5 make your speaker cone according to that function. For example, ifmake you want to 0.50 0 0.01 0.02 0.03 0.04 0.05 0.01 0.02 0.03 0.04 0.05 speaker oscillate following the sum: play an A – C# - E chord, you can separately make three speakers oscillate Time Time according to the functions: 1 0 4 12 1.5 Frequency spectrum for pure A 4 Frequency spectrum7 for A−C#−E chord 7 12 ) + sin( sin(440 ⋅ 2πt ), sin( 440 ⋅ 2sin(−0.5 ⋅440 2πt ),⋅ 2πtsin( 440 440 ⋅ 2 ⋅⋅22πt⋅)2πt ) + sin( 440 ⋅ 2 ⋅ 2πt ) Pure A Here again, if you want the different notes to haveA−C#−E different chordvolumes, you can multiply each sine w If you want note louder or softer than the others, you −1 can multiply the whole function by a constant 1 by volume a constant. to increase or3 decrease the of that note. Each speaker will make pressure waves in the air, and frequenza 0 0.01 frequenza 0.02 0.03 0.04 0.05 frequenza 0 0.01 0.02 0.03 0.04 0.05frequenza Time these pressure waves from different speakers will overlap as they moveTime toward your ear. By the time 2 for pure Frequency spectrum for A−C#−E chord here to hear anspeaker A – C# - E chord. Click here to hearwaves an A will – C# - E – A2 chord. The 0.5 they are at your ear, Frequency you willspectrum beClick unable toAtell which they came from; the pressure 5 1.5 1 graphs on the preceding page show what happens when you add the three to make the A have been superimposed on one another, to Pure A or added to one another. Your ear is amazing at being ablefunctions A−C#−E chord 4 C# E chord and the A – C# E – A2 chord. respond to the the three notes being played at once. This 0 different frequencies separately to perceive 0 10 200 400 600 800 1000 200 400 600 800 explains why 0you can simply add the three functions above and make the speaker cone1000 of a single 3 Frequency Frequency spettro Frequency spectrum speaker oscillateFrequency following the sum: spectrum for spoken long A Frequency spectrum for spoken long E 2 di frequenza 4 0.8 1 0.5so far are very 7simple, being sine functions The sounds we have generated or sums of a few sine 12 12 1 sin( 440 ⋅ 2 π t ) + sin( 440 ⋅ 2 ⋅ 2 π t ) + sin( 440 ⋅ 2 ⋅ 2 π t ) functions, and they sound very much computer-generated. Real sounds are more complex, and it 0.8 0.6 Here again, if 0you want entirely the different to have different volumes, you can multiply each sine wave clearnotes that sine functions have anything to do with them. However, it can be shown that an 0 200 400 600 800 1000 0 200 400 600 800 1000 0.6 0 by a constant. “continuous” sound (that is, a0.4sound that is Frequency constant, or unchanging over time) can be reproduced Frequency 0.4 sum of sine functions frequencies and That is, if a speaker is playing a Frequency spectrum for spoken long A of different Frequency spectrum for amplitudes. spoken long E 1 0.8 0.2 Click here to hear an A – C# E chord. Click here to hear an A – C# E – A2 chord. The continuous sound by making the speaker cone follow some function L(t) over the time interval fro 0.2 graphs on the0.8precedingto page show what when you add the three functions to make the A– 1 second, thenhappens we can write L(t) as a sum of sine functions this way: 0.6 0 C# - E chord00.6 and the A – C# E – A2 chord. 0 200 400 600 800 1000 0 200 400 600 800 1000 5 −0.5 Strength 12 Strength Strength Strength Strength 4 one −1 12 Strength Strength Cos’è il suono? //Sinusoidi Frequency spectrum e toni puri Frequency Frequency 20 , 000 0.4 Frequency OO 0.4 Frequency spectrum for spoken long O L(spectrum t ) = foraspoken k sin( k ⋅ 2 t ) 0.5 0.8 20 k = 0.2 The sounds we 0.2 have generated so far are very simple, being sine functions or sums of a few sine The number k is the frequency, and forsounds soundsare thatmore humans can hear, should use frequencies f 0.4 functions, and 0they sound very much computer-generated. Real complex, and itwe isn’t 0.6 0 20 400 Hertzhave to about Hertz. we we can’t hear at 20,000 0 sine 200functions 600 800 20,000 1000 200 age, 400 600 800 1000 that entirely clear anything to do with0 As them. However, it can be sounds shown any Hertz very well anym 0.3that Frequency mechanical devices that hum because of alternating cu Click here for: 20 Hz, 60 Hz,0.4(the sound of Frequency π Strength Strength • Se il segnale non è periodico ∑ 0 0.3 0.2 200 400 600 Frequency 800 1000 L (t ) = 0.1 20 , 000 ∑a k = 20 Strength Strength “continuous” sound (that spectrum is, a sound thatlong is constant, or unchanging over time) can OO be reproduced as a Frequency spoken O 10000 Hz, 16000 Frequency for spoken 0.2 60forHz) 100 Hz, Hz,spectrum 20000Hz. Beisaware thata some of these may be outsid sum of sine functions ofbeing different frequencies and amplitudes. That is, if a speaker playing 0.5 0.8 0.2 range of your speakers or your ears! The numbers a are called the for frequency k. continuous 0.1 sound by making the speaker cone follow some function L(t) over kthe time intervalamplitudes from 0 0.4 0.6 to 1 second, then we caneasy writetoL(t) a sum of sine this way: findasthe values of afunctions integrals: 0 0 k using k 0 0.4 200 sin( k ⋅ 2πt ) 0.2 400 600 1 Frequency 800 1000 a k = ∫ sin(k ⋅ 2πt ) L(t )dt. 0 (Actually, the that whole story can – forhear, thiswe to be exactly you from either need to use cosine The number k 0is the frequency, andthis forisn’t sounds humans should use correct, frequencies 0 0 200 functions 400 600 800need 1000 0 to shift 200 each 800 horizontally orwe you tocan’t be able sine600 function on the t axis, but this is clo 20 Hertz to about 20,000 Hertz. As age, we hear sounds at400 20,000 Hertz very1000 well anymore. Frequency Frequency Click here for: 20 Hz, 60 Hz, (the sound of mechanical devices that hum because of alternating current being 60 Hz) 100 Hz, 10000 Hz, 16000 Hz, 20000Hz. Be aware that some of these may be outside the range of your speakers or your ears! The numbers a k are called the amplitudes for frequency k. It is easy to find the values of a k using integrals: 1 a k = ∫ sin(k ⋅ 2πt ) L(t )dt. 0 (Actually, this isn’t the whole story – for this to be exactly correct, you either need to use cosine functions or you need to be able to shift each sine function horizontally on the t axis, but this is close Cos’è il suono? //Suoni complessi duzione ai sistemi lineari • Non sono molto comuni fra i suoni che sentiamo tutti i giorni perché poche vibrazioni sono così pure • I suoni più comuni nel mondo sono suoni complessi (e.g., voci umane, di uccelli, suoni di macchine etc.) • Però tutti i suoni complessi possono essere descritti come combinazioni di onde sinusoidali (teorema di Fourier). Il comportamento di un sistema lineare spazio-invariante è completamente caratte risposta all’impulso luminoso (x, y), cioè dalla PSF h(x, y) = S( (x, y)) Data un’immagine in ingresso f , un sistema lineare spazio-invariante caratterizza produce un’immagine in uscita g effettuando la convoluzione g =f ⇥h= +⇤ +⇤ ⇤ ⇤ f (x x⇥ , y y ⇥ )h(x⇥ , y ⇥ )dx⇥ dy ⇥ ima analisi, conoscendo h conosciamo perfettamente il sistema. Cos’è il suono? ile, dalla definizione, dimostrare che la convoluzione gode delle proprietà commutativ //Sinusoidi e toni puri finitiva: • Generalizziamo la rappresentazione del segnale acustico input f ⇥h=h⇥f (f ⇥ h1 ) ⇥ h2 = f ⇥ (h1 ⇥ h2 ) Frequenze oniamo un segnale f (t) = A cos ⇤t oppure f (t) = A sin ⇤t. L’output di un sistema LS to e scalato Formule di Eulero A cos(⇤t + ⇥) oppure g(t) = A sin(⇤t + ⇥) ⇥ ⇥ alizzando f (t) = Aeiwt g(t) = A⇥ eiwt rappresentazione in campo complesso Rilevamento di bordi Cos’è il suono? //Sinusoidi e toni puri Cos’è il suono? //Sinusoidi e toni puri • Se il segnale non è periodico Snippet of a piece of music Speaker position 0.1 0.05 0 −0.05 −0.1 0 0.005 0.01 0.015 0.02 0.025 0.03 Time in seconds 0.035 Digital samples are taken 44100 times per second n 0.1 0.05 0.04 0.045 0.05 Cos’è il suono? //Sinusoidi e toni puri hich makes questions of convergence of the integral that much more delicate. Furthermore, pplying the Fourier inversion formula • Se il segnale non èZperiodico 1 f (t) = e2⇡ist fˆ(s) ds rappresentazione del segnale 1 nvolves knowing first that e fˆ(s) can be integrated and that the integration (Antitrasformata leads back di Fourier) o f (t). As a cautionary example, the trig functions sine and cosine – the building blocksspettro of periodic di frequenza henomena! – do not have simple Fourier transforms. More general theories of (Trasformata integration di Fourier) otwithstanding, there is no way to make sense of Z 1 Z 1 2⇡ist e cos 2⇡t dt or e 2⇡ist sin 2⇡t dt 2⇡ist 1 1 s any kind of classical functions. Plainly there’s a lot going on. Why then the certainty in employing these Secrets of the niverse – and believe me, they’re fully employed. Several reasons. First, by now there a quite sophisticated mathematical understanding of the Fourier transform and Fourier nversion, including definitions that go beyond the formulas via integrals. This culminates ith the theory of ‘distributions,’ which is the rigorous treatment of ‘delta functions’ and he like.2 Second, nature seems to take care of the existence of the integrals quite nicely, hank you, not to mention Fourier inversion. Recall that your inner ear finds the frequency ontent of a given signal (signals which generally are not periodic) and that your brain must hen take the inverse transform to get the signal back. In the field of optics one discovers hat lenses and prisms have the e↵ect of taking a Fourier transform. Finally, for modern, omputational uses of Fourier analysis, which are ubiquitous, one works with discrete data ot continuous signals. It’s a discrete form of the Fourier transform and the inverse transform hat are used, with finite sums replacing integrals. There are no questions of convergence or xistence for such finite sums.3 There are other questions, but not the same questions. Cos’è il suono? //Sinusoidi toni An example. Before doing anythingeelse grandpuri and sweeping, let’s do something modest nd confined. Let’s compute an example. Take ( 1, • Esempio: ⇧(t) = 0, 1 2 t otherwise 1 2 his is called, variously, the ‘top hat’ function, the ‘rect’ function (for rectangle), the ‘inicator’ function for the interval [ 1/2, 1/2], or the ‘characteristic’ function for the interval 1/2, 1/2]. One can debate whether to define the function at the endpoints as I bhave. I function zero outside [ 1/2, 1/2] the limits on the integral ⇧ only efuse to beisdrawn into the of debate – for oursopurposes it will never matter.defining The graph is: go bo The function is zero outside of [ 1/2, 1/2] so the limits on the integral defining ⇧ 1/2 to 1/2. The integration is straightforward: 2Though delta functions are often associated with P. Dirac from 1/2 1/2. The is straightforward: his to treatment of integration quantum mechanics, Z 1 Z and 1/2 Z Z heir operational use bwas realized much earlier by O. Heaviside in his 2⇡isx elucidation of Maxwell’s 1theory of 2⇡isx 2⇡isx b ⇧(s) = ⇧(x)e dx = e dx ⇧(s) = ⇧(x)e dx = ectromagnetism. 3The 1 1/2 1 discrete form of the Fourier transform is essentially a Riemann sum approximation to the integral, 1/2 1/2 This, the DFT (discrete Fourier transform), 1 is the at least it can be developed from that of view. 1 point2⇡isx = e 2⇡isx ndamental operator in applications. It is not = e to be confused with the FFT (Fast Fourier Transform). 2⇡is The 1/2 FT is an algorithm for the efficient 2⇡is calculation of the1/2 DFT. Keep this straight. It’s easy to detect when 1 mebody doesn’t know what they’re 1talking about when they casually refer to the FFT when = they mean, (e ⇡is e⇡is ) 2⇡is ⇡is ⇡is should mean the DFT. = (e e ) he special values 2⇡is 1 = 2i sin ⇡s 2⇡is sin ⇡s = ⇡s ( 1, sinc s = 0, 1/2 e 2⇡isx dx 1/2 1 2i sin ⇡s 2⇡is sin ⇡s = ⇡s 4 = Note the special values ( 1, sinc s = 0, s = 0, s an integer other than 0. You may have thought that sin x/x only comes up as an example of 0/0 in calculus s = 0, Engineers see this curve when they sleep, and when they shop: and could have no possible interest beyond that. No, no! It’s in your CD player, for ex s an integer other than 0. for reasons we’ll explain. In fact, the function comes up so often it’s given a name, th Cos’è il suono? //Sinusoidi e toni puri • Se il segnale non è periodico Cos’è il suono? //Spettro armonico • Spettro armonico: causato da una semplice fonte di vibrazioni (pe. corda di chitarra o un sassofono) • Prima armonica: la componente fondamentale più bassa del suono • Suoni con la stessa armonica fondamentale possono essere percepiti come diversi Cos’è il suono? //il timbro • Il timbro è quella particolare qualità del suono che permette di giudicare diversi due suoni con uguale intensità e altezza. • Rappresenta quell'attributo della sensazione uditiva che consente all'ascoltatore d'identificare la fonte sonora, rendendola distinguibile da ogni altra. • Suggerisce numerose analogie con il colore: il timbro viene designato come colore del suono tanto in inglese (tone-colour) quanto in tedesco (klangfarbe) • Concezione classica, basata sulla teoria del suono di Helmholtz: • il timbro viene determinato sulla base della sola composizione spettrale del suono, ossia in base alla distribuzione dell'energia delle diverse componenti di frequenza che compongono il suono. Il sistema uditivo • Come sono percepiti e riconosciuti i suoni dal sistema percettivo acustico? • L’udito si è evoluto per milioni di anni • Animali diversi hanno diverse capacità uditive Il sistema uditivo Orecchio interno trasduce i suoni (converte energia meccanica in risposte neurali) Orecchio esterno raccoglie e trasforma i suoni Orecchio medio amplifica i suoni Il sistema uditivo //orecchio esterno • Il padiglione + canale uditivo formano l’orecchio esterno • I suoni sono per prima cosa raccolti dall’ambiente esterno attraverso il padiglione • Le onde sonore sono incanalate dal padiglione dentro il canale uditivo • La lunghezza e la forma del canale uditivo intensificano le frequenze del suono • Il fine principale del canale uditivo è quello di isolare la struttura al suo fondo: la membrana timpanica: • Il timpano è un sottile strato di pelle alla fine del canale uditivo esterno che vibra in risposta ai suoni • è il confine fra l’orecchio esterno e quello medio Il sistema uditivo //orecchio esterno • Il fine principale del canale uditivo è quello di isolare la struttura al suo fondo: la membrana timpanica: • Il timpano è un sottile strato di pelle alla fine del canale uditivo esterno che vibra in risposta ai suoni • è il confine fra l’orecchio esterno e quello medio Il sistema uditivo Orecchio interno trasduce i suoni (converte energia meccanica in risposte neurali) Orecchio esterno raccoglie e trasforma i suoni Orecchio medio amplifica i suoni Il sistema uditivo //orecchio medio • Consiste di tre ossicini che amplificano la pressione dei suoni per bilanciare le impedenze acustiche diverse fra l’aria e l’acqua: • Martello, Incudine e Staffa. Questi sono gli ossi più piccoli di tutto il corpo • La staffa trasmette le vibrazioni delle onde sonore alla finestra ovale un’altra membrana che rappresenta il confine fra orecchio medio e orecchio interno Il sistema uditivo //orecchio medio • Consiste di tre ossicini che amplificano la pressione dei suoni per bilanciare le impedenze acustiche diverse fra l’aria e l’acqua: • Martello, Incudine e Staffa. Questi sono gli ossi più piccoli di tutto il corpo • La staffa trasmette le vibrazioni delle onde sonore alla finestra ovale un’altra membrana che rappresenta il confine fra orecchio medio e orecchio interno Il sistema uditivo //orecchio medio • L’amplificazione della pressione provvista dagli ossicini è essenziale per la capacità di sentire suoni deboli • Amplificazione del suono: • giunture degli ossicini • Gli ossicini sono comunque importanti anche per i suoni molto forti • membrana timpanica più larga della base delle staffe • La finestra ovale (della coclea) è l’interfaccia fra orecchio medio e interno • L’orecchio interno è formato da una camera piena di liquido: • richiede più energia per essere mossa Il sistema uditivo //orecchio medio; riflesso acustico • Muscoli: • tensor timpani • stapedio • si tendono per ridurre l’amplificazioni di suoni forti: riflesso acustico • seguono l’inizio dei suoni forti di circa un quinto di secondo quindi non si può avere protezione contro suoni bruschi come lo sparo di una pistola Il sistema uditivo Orecchio interno trasduce i suoni (converte energia meccanica in risposte neurali) Orecchio esterno raccoglie e trasforma i suoni Orecchio medio amplifica i suoni Il sistema uditivo //orecchio interno • Orecchio interno: cambiamenti fini nella pressione dei suoni vengono tradotti in segnali neurali • La sua funzione può essere assimilabile a quella della retina per la visione Il sistema uditivo //orecchio interno:coclea • Le vibrazioni trasmesse attraverso le membrane timpaniche e gli ossicini dell’orecchio medio fanno in modo che la staffa faccia oscillare la finestra ovale fuori e dentro il canale vestibolare alla base della coclea • Qualsiasi pressione rimanente è trasmessa attraverso l’ elicotrema indietro alla base cocleare attraverso il canale timpanico dove viene assorbita da un’altra membrana: la finestra rotonda Il sistema uditivo //orecchio interno: coclea • Le vibrazioni trasmesse attraverso le membrane timpaniche e gli ossicini dell’orecchio medio fanno in modo che la staffa faccia oscillare la finestra ovale fuori e dentro il canale vestibolare alla base della coclea • Qualsiasi pressione rimanente è trasmessa attraverso l’elicotrema indietro alla base cocleare attraverso il canale timpanico dove viene assorbita da un’altra membrana: la finestra rotonda Il sistema uditivo //orecchio interno: coclea • Canali e membrane cocleari • Coclea: Struttura fatta a spirale dell’orecchio interno contenente l’organo di Corti • divisa in tre canali paralleli è riempita da un liquido acquoso Il sistema uditivo //orecchio interno:coclea • I tre canali della coclea • Canale timpanico • Canale vestibolare • Canale di mezzo • I tre canali sono separati da membrane: la membrana di Reissner e quella basilare Organo del Corti Il sistema uditivo //orecchio interno:coclea • I tre canali della coclea • Canale timpanico • Canale vestibolare • Canale di mezzo • I tre canali sono separati da membrane: la membrana di Reissner e quella basilare Il sistema uditivo //orecchio interno:coclea • I tre canali della coclea • Canale timpanico • Canale vestibolare • Canale di mezzo • I tre canali sono separati da membrane: la membrana di Reissner e quella basilare • Svolge la funzione fondamentale di analizzare il suono in frequenza Il sistema uditivo //orecchio interno: codifica nella coclea Codifica tonotopica: Parti diverse della coclea sono sensibili a frequenze diverse cioè ogni particolare zona della coclea risponde in maniera più robusta ad una determinata frequenza e meno ad altre Il sistema uditivo //orecchio interno: organo di Corti • L’organo di Corti • I movimenti degli strati della coclea sono tradotti in segnali neurali dalle strutture nell’ organo di Corti che si estende sulla parete superiore della membrana basilare • Questa è fatta da neuroni specializzati chiamati cellule ciliari, da dendriti delle fibre del nervo uditivo che terminano alla base delle cellule ciliari e da una impalcatura di cellule di supporto place code Il sistema uditivo //orecchio interno: organo di Corti • L’organo di Corti • I movimenti degli strati della coclea sono tradotti in segnali neurali dalle strutture nell’ organo di Corti che si estende sulla parete superiore della membrana basilare • Questa è fatta da neuroni specializzati chiamati cellule ciliari, da dentriti delle fibre del nervo uditivo che terminano alla base delle cellule ciliari e da una impalcatura di cellule di supporto • disposte in 4 righe che corrono lungo la membrana basilare Il sistema uditivo //orecchio interno: organo di Corti Il sistema uditivo //orecchio interno: organo di Corti le stereocilia regolano l’afflusso di ioni nelle cellule ciliari Il sistema uditivo //orecchio interno: organo di Corti • Cellule ciliari interne ed esterne • Cellule ciliari interne: Convogliano quasi tutta l’informazione sui suoni al cervello • Cellule ciliari esterne: Convogliano le informazioni dal cervello (uso di fibre efferenti). Queste sono coinvolte in processi di feedback molto elaborati • Le scariche dei neuroni che formano il nervo acustico in attività neurale completano il processo di trasduzione dei segnali da onde sonore a segnali neuronali